Base | Representation |
---|---|
bin | 11110110101001001… |
… | …110011000001000111 |
3 | 10011110002001020001121 |
4 | 132311021303001013 |
5 | 1020244111443211 |
6 | 23112513534411 |
7 | 2251230326344 |
oct | 366511630107 |
9 | 104402036047 |
10 | 33104015431 |
11 | 13048398843 |
12 | 64ba574407 |
13 | 3177497a16 |
14 | 18607a97cb |
15 | cdb3b7271 |
hex | 7b5273047 |
33104015431 has 2 divisors, whose sum is σ = 33104015432. Its totient is φ = 33104015430.
The previous prime is 33104015423. The next prime is 33104015443. The reversal of 33104015431 is 13451040133.
It is a weak prime.
It is an emirp because it is prime and its reverse (13451040133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33104015431 - 23 = 33104015423 is a prime.
It is a super-2 number, since 2×331040154312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 33104015396 and 33104015405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33104015491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16552007715 + 16552007716.
It is an arithmetic number, because the mean of its divisors is an integer number (16552007716).
Almost surely, 233104015431 is an apocalyptic number.
33104015431 is a deficient number, since it is larger than the sum of its proper divisors (1).
33104015431 is an equidigital number, since it uses as much as digits as its factorization.
33104015431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 33104015431 its reverse (13451040133), we get a palindrome (46555055564).
The spelling of 33104015431 in words is "thirty-three billion, one hundred four million, fifteen thousand, four hundred thirty-one".
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