Base | Representation |
---|---|
bin | 110000001011101101100… |
… | …111010011101000111101 |
3 | 102201112120001002221202002 |
4 | 300023231213103220331 |
5 | 413222123444302143 |
6 | 11013034210512045 |
7 | 461135265601634 |
oct | 60135547235075 |
9 | 12645501087662 |
10 | 3311111322173 |
11 | 1067264025866 |
12 | 455870595625 |
13 | 1b030c662255 |
14 | b6389a0651b |
15 | 5b1e26315b8 |
hex | 302ed9d3a3d |
3311111322173 has 2 divisors, whose sum is σ = 3311111322174. Its totient is φ = 3311111322172.
The previous prime is 3311111322161. The next prime is 3311111322209. The reversal of 3311111322173 is 3712231111133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2133361123609 + 1177750198564 = 1460603^2 + 1085242^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3311111322173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3311111322133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655555661086 + 1655555661087.
It is an arithmetic number, because the mean of its divisors is an integer number (1655555661087).
Almost surely, 23311111322173 is an apocalyptic number.
It is an amenable number.
3311111322173 is a deficient number, since it is larger than the sum of its proper divisors (1).
3311111322173 is an equidigital number, since it uses as much as digits as its factorization.
3311111322173 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2268, while the sum is 29.
The spelling of 3311111322173 in words is "three trillion, three hundred eleven billion, one hundred eleven million, three hundred twenty-two thousand, one hundred seventy-three".
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