Base | Representation |
---|---|
bin | 110000001011101101101… |
… | …001111001111100000010 |
3 | 102201112120002101120010010 |
4 | 300023231221321330002 |
5 | 413222124133101310 |
6 | 11013034233245350 |
7 | 461135304436545 |
oct | 60135551717402 |
9 | 12645502346103 |
10 | 3311112003330 |
11 | 10672644505aa |
12 | 455870863856 |
13 | 1b030c8402c1 |
14 | b6389b4285c |
15 | 5b1e2718320 |
hex | 302eda79f02 |
3311112003330 has 64 divisors (see below), whose sum is σ = 7974538231680. Its totient is φ = 879871179264.
The previous prime is 3311112003271. The next prime is 3311112003341. The reversal of 3311112003330 is 333002111133.
3311112003330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 3311112003297 and 3311112003306.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11477212 + ... + 11762168.
It is an arithmetic number, because the mean of its divisors is an integer number (124602159870).
Almost surely, 23311112003330 is an apocalyptic number.
3311112003330 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3311112003330 is an abundant number, since it is smaller than the sum of its proper divisors (4663426228350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3311112003330 is a wasteful number, since it uses less digits than its factorization.
3311112003330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 286323.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 3311112003330 its reverse (333002111133), we get a palindrome (3644114114463).
The spelling of 3311112003330 in words is "three trillion, three hundred eleven billion, one hundred twelve million, three thousand, three hundred thirty".
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