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331114103 is a prime number
BaseRepresentation
bin10011101111000…
…110011001110111
3212002001100011022
4103233012121313
51134231122403
652504531355
711130265145
oct2357063167
9762040138
10331114103
1115a9a5a21
1292a80b5b
13537a2c08
1431d92595
151e107d38
hex13bc6677

331114103 has 2 divisors, whose sum is σ = 331114104. Its totient is φ = 331114102.

The previous prime is 331114097. The next prime is 331114111. The reversal of 331114103 is 301411133.

It is a weak prime.

It is an emirp because it is prime and its reverse (301411133) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-331114103 is a prime.

It is a super-7 number, since 7×3311141037 (a number of 61 digits) contains 7777777 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331114403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165557051 + 165557052.

It is an arithmetic number, because the mean of its divisors is an integer number (165557052).

Almost surely, 2331114103 is an apocalyptic number.

331114103 is a deficient number, since it is larger than the sum of its proper divisors (1).

331114103 is an equidigital number, since it uses as much as digits as its factorization.

331114103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 331114103 is about 18196.5409625016. The cubic root of 331114103 is about 691.8191184993.

Adding to 331114103 its reverse (301411133), we get a palindrome (632525236).

The spelling of 331114103 in words is "three hundred thirty-one million, one hundred fourteen thousand, one hundred three".