Base | Representation |
---|---|
bin | 100101101001010011000001… |
… | …1100100100000000001000100 |
3 | 1121102102211202201001211111200 |
4 | 1023102212003210200001010 |
5 | 321400223401024101312 |
6 | 3132131341502102500 |
7 | 126514306220062314 |
oct | 11322460344400104 |
9 | 1542384681054450 |
10 | 331131301003332 |
11 | 96565aa5928665 |
12 | 3117b56a87aa30 |
13 | 1129c7173b0c7b |
14 | 5baabaa3d7444 |
15 | 28437420500dc |
hex | 12d2983920044 |
331131301003332 has 72 divisors (see below), whose sum is σ = 848821966312320. Its totient is φ = 108821657562240.
The previous prime is 331131301003309. The next prime is 331131301003343. The reversal of 331131301003332 is 233300103131133.
331131301003332 is a `hidden beast` number, since 3 + 3 + 1 + 1 + 313 + 0 + 10 + 0 + 3 + 332 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 331131301003296 and 331131301003305.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 393390169 + ... + 394231007.
It is an arithmetic number, because the mean of its divisors is an integer number (11789193976560).
Almost surely, 2331131301003332 is an apocalyptic number.
It is an amenable number.
331131301003332 is an abundant number, since it is smaller than the sum of its proper divisors (517690665308988).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
331131301003332 is a wasteful number, since it uses less digits than its factorization.
331131301003332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 994993 (or 994988 counting only the distinct ones).
The product of its (nonzero) digits is 4374, while the sum is 27.
Adding to 331131301003332 its reverse (233300103131133), we get a palindrome (564431404134465).
The spelling of 331131301003332 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, three hundred one million, three thousand, three hundred thirty-two".
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