Base | Representation |
---|---|
bin | 110000001011111010101… |
… | …101110011011100001111 |
3 | 102201120010100201022011111 |
4 | 300023322231303130033 |
5 | 413223101232112403 |
6 | 11013112102032451 |
7 | 461143605122314 |
oct | 60137255633417 |
9 | 12646110638144 |
10 | 3311331129103 |
11 | 1067367106a88 |
12 | 455912118727 |
13 | 1b0346062b1a |
14 | b63aaca2d0b |
15 | 5b206a9e56d |
hex | 302fab7370f |
3311331129103 has 2 divisors, whose sum is σ = 3311331129104. Its totient is φ = 3311331129102.
The previous prime is 3311331129101. The next prime is 3311331129229. The reversal of 3311331129103 is 3019211331133.
It is a weak prime.
It is an emirp because it is prime and its reverse (3019211331133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3311331129103 - 21 = 3311331129101 is a prime.
Together with 3311331129101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3311331129101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655665564551 + 1655665564552.
It is an arithmetic number, because the mean of its divisors is an integer number (1655665564552).
Almost surely, 23311331129103 is an apocalyptic number.
3311331129103 is a deficient number, since it is larger than the sum of its proper divisors (1).
3311331129103 is an equidigital number, since it uses as much as digits as its factorization.
3311331129103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 31.
The spelling of 3311331129103 in words is "three trillion, three hundred eleven billion, three hundred thirty-one million, one hundred twenty-nine thousand, one hundred three".
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