Base | Representation |
---|---|
bin | 100101101001010100000000… |
… | …0111011010101001111001011 |
3 | 1121102110001012021111021022112 |
4 | 1023102220000323111033023 |
5 | 321400242202424443431 |
6 | 3132132330311412535 |
7 | 126514412305333451 |
oct | 11322500073251713 |
9 | 1542401167437275 |
10 | 331133404140491 |
11 | 96566985009747 |
12 | 3117ba5708414b |
13 | 1129c991029a24 |
14 | 5baad2985c9d1 |
15 | 28438169d6c2b |
hex | 12d2a00ed53cb |
331133404140491 has 2 divisors, whose sum is σ = 331133404140492. Its totient is φ = 331133404140490.
The previous prime is 331133404140463. The next prime is 331133404140493. The reversal of 331133404140491 is 194041404331133.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331133404140491 is a prime.
Together with 331133404140493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (331133404140493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165566702070245 + 165566702070246.
It is an arithmetic number, because the mean of its divisors is an integer number (165566702070246).
Almost surely, 2331133404140491 is an apocalyptic number.
331133404140491 is a deficient number, since it is larger than the sum of its proper divisors (1).
331133404140491 is an equidigital number, since it uses as much as digits as its factorization.
331133404140491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 41.
The spelling of 331133404140491 in words is "three hundred thirty-one trillion, one hundred thirty-three billion, four hundred four million, one hundred forty thousand, four hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •