331134000431133 has 8 divisors (see below), whose sum is σ = 441516522384000. Its totient is φ = 220753739382848.

The previous prime is 331134000431119. The next prime is 331134000431153.

331134000431133 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 331134000431133 - 2⁴⁵ = 295949628342301 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 331134000431133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (331134000431153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 564884373 + ... + 565470266.

It is an arithmetic number, because the mean of its divisors is an integer number (55189565298000).

Almost surely, 2^{331134000431133} is an apocalyptic number.

It is an amenable number.

331134000431133 is a deficient number, since it is larger than the sum of its proper divisors (110382521952867).

331134000431133 is a wasteful number, since it uses less digits than its factorization.

331134000431133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1130452291.

The product of its (nonzero) digits is 11664, while the sum is 30.

It can be divided in two parts, 331134000 and 431133, that added together give a palindrome (331565133).

The spelling of 331134000431133 in words is "three hundred thirty-one trillion, one hundred thirty-four billion, four hundred thirty-one thousand, one hundred thirty-three".