Base | Representation |
---|---|
bin | 110000001100101001110… |
… | …100001011100101100100 |
3 | 102201122011102121200001010 |
4 | 300030221310023211210 |
5 | 413231211030030040 |
6 | 11013322330502220 |
7 | 461202311534136 |
oct | 60145164134544 |
9 | 12648142550033 |
10 | 3312121330020 |
11 | 1067732164698 |
12 | 455ab2894970 |
13 | 1b0440994729 |
14 | b6443bdb056 |
15 | 5b25113ce80 |
hex | 30329d0b964 |
3312121330020 has 96 divisors (see below), whose sum is σ = 9308576083968. Its totient is φ = 879934914432.
The previous prime is 3312121330009. The next prime is 3312121330027. The reversal of 3312121330020 is 200331212133.
It is not an unprimeable number, because it can be changed into a prime (3312121330027) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 99605037 + ... + 99638283.
It is an arithmetic number, because the mean of its divisors is an integer number (96964334208).
Almost surely, 23312121330020 is an apocalyptic number.
3312121330020 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3312121330020 is an abundant number, since it is smaller than the sum of its proper divisors (5996454753948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3312121330020 is a wasteful number, since it uses less digits than its factorization.
3312121330020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39409 (or 39407 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 3312121330020 its reverse (200331212133), we get a palindrome (3512452542153).
The spelling of 3312121330020 in words is "three trillion, three hundred twelve billion, one hundred twenty-one million, three hundred thirty thousand, twenty".
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