Search a number
-
+
331214808412133 is a prime number
BaseRepresentation
bin100101101001111001111010…
…0111111111110111111100101
31121102201211022110222201212022
41023103303310333332333211
5321403110411423142013
63132233552111432525
7126523323501251462
oct11323636477767745
91542654273881768
10331214808412133
11965984586618a8
1231193795225745
13112a75650776b9
145bb0c4ccdc669
1528459cd3e1008
hex12d3cf4ffefe5

331214808412133 has 2 divisors, whose sum is σ = 331214808412134. Its totient is φ = 331214808412132.

The previous prime is 331214808412129. The next prime is 331214808412217.

It is a happy number.

331214808412133 is nontrivially palindromic in base 10.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 184678505584609 + 146536302827524 = 13589647^2 + 12105218^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 331214808412133 - 22 = 331214808412129 is a prime.

It is a super-2 number, since 2×3312148084121332 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331214808412333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165607404206066 + 165607404206067.

It is an arithmetic number, because the mean of its divisors is an integer number (165607404206067).

Almost surely, 2331214808412133 is an apocalyptic number.

It is an amenable number.

331214808412133 is a deficient number, since it is larger than the sum of its proper divisors (1).

331214808412133 is an equidigital number, since it uses as much as digits as its factorization.

331214808412133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 331776, while the sum is 44.

The spelling of 331214808412133 in words is "three hundred thirty-one trillion, two hundred fourteen billion, eight hundred eight million, four hundred twelve thousand, one hundred thirty-three".