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33125244252134 = 216562622126067
BaseRepresentation
bin1111000100000100100100…
…11010101010111111100110
311100021202001020010020221012
413202002102122222333212
513320211000012032014
6154241305505422222
76656135301255446
oct742022232527746
9140252036106835
1033125244252134
11a611378897121
12386ba8933a972
13156390a794488
148273adcac126
153c69e4ac5c3e
hex1e20926aafe6

33125244252134 has 4 divisors (see below), whose sum is σ = 49687866378204. Its totient is φ = 16562622126066.

The previous prime is 33125244252077. The next prime is 33125244252179. The reversal of 33125244252134 is 43125244252133.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 33125244252091 and 33125244252100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8281311063032 + ... + 8281311063035.

It is an arithmetic number, because the mean of its divisors is an integer number (12421966594551).

Almost surely, 233125244252134 is an apocalyptic number.

33125244252134 is a deficient number, since it is larger than the sum of its proper divisors (16562622126070).

33125244252134 is a wasteful number, since it uses less digits than its factorization.

33125244252134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16562622126069.

The product of its digits is 691200, while the sum is 41.

Subtracting 33125244252134 from its reverse (43125244252133), we obtain a palindrome (9999999999999).

The spelling of 33125244252134 in words is "thirty-three trillion, one hundred twenty-five billion, two hundred forty-four million, two hundred fifty-two thousand, one hundred thirty-four".

Divisors: 1 2 16562622126067 33125244252134