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33130029973 is a prime number
BaseRepresentation
bin11110110110101101…
…000010001110010101
310011111212222220022011
4132312231002032111
51020322241424343
623115243304221
72251664415445
oct366655021625
9104455886264
1033130029973
1113061046967
12650721b071
13317c9a5941
14186401c125
15cdd80529d
hex7b6b42395

33130029973 has 2 divisors, whose sum is σ = 33130029974. Its totient is φ = 33130029972.

The previous prime is 33130029967. The next prime is 33130029979. The reversal of 33130029973 is 37992003133.

It is a balanced prime because it is at equal distance from previous prime (33130029967) and next prime (33130029979).

It can be written as a sum of positive squares in only one way, i.e., 22742751249 + 10387278724 = 150807^2 + 101918^2 .

It is a cyclic number.

It is not a de Polignac number, because 33130029973 - 25 = 33130029941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33130029979) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16565014986 + 16565014987.

It is an arithmetic number, because the mean of its divisors is an integer number (16565014987).

Almost surely, 233130029973 is an apocalyptic number.

It is an amenable number.

33130029973 is a deficient number, since it is larger than the sum of its proper divisors (1).

33130029973 is an equidigital number, since it uses as much as digits as its factorization.

33130029973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 91854, while the sum is 40.

The spelling of 33130029973 in words is "thirty-three billion, one hundred thirty million, twenty-nine thousand, nine hundred seventy-three".