Base | Representation |
---|---|
bin | 1111000100010001011001… |
… | …10101110000101111000111 |
3 | 11100022101211002220002212012 |
4 | 13202020230311300233013 |
5 | 13320314100240341403 |
6 | 154244405043244435 |
7 | 6656501032253423 |
oct | 742105465605707 |
9 | 140271732802765 |
10 | 33132130012103 |
11 | a614291703541 |
12 | 387128b37971b |
13 | 156446720c165 |
14 | 8278645abb83 |
15 | 3c6c99375ed8 |
hex | 1e222cd70bc7 |
33132130012103 has 4 divisors (see below), whose sum is σ = 33132153135120. Its totient is φ = 33132106889088.
The previous prime is 33132130012073. The next prime is 33132130012127. The reversal of 33132130012103 is 30121003123133.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 33132130012103 - 26 = 33132130012039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (33132130012183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9259418 + ... + 12328871.
It is an arithmetic number, because the mean of its divisors is an integer number (8283038283780).
Almost surely, 233132130012103 is an apocalyptic number.
33132130012103 is a deficient number, since it is larger than the sum of its proper divisors (23123017).
33132130012103 is a wasteful number, since it uses less digits than its factorization.
33132130012103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23123016.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 33132130012103 its reverse (30121003123133), we get a palindrome (63253133135236).
The spelling of 33132130012103 in words is "thirty-three trillion, one hundred thirty-two billion, one hundred thirty million, twelve thousand, one hundred three".
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