331344121443133 has 4 divisors (see below), whose sum is σ = 331359663662560. Its totient is φ = 331328579223708.

The previous prime is 331344121443067. The next prime is 331344121443149.

331344121443133 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-331344121443133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (331344121443733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7771077735 + ... + 7771120372.

It is an arithmetic number, because the mean of its divisors is an integer number (82839915915640).

Almost surely, 2^{331344121443133} is an apocalyptic number.

It is an amenable number.

331344121443133 is a deficient number, since it is larger than the sum of its proper divisors (15542219427).

331344121443133 is a wasteful number, since it uses less digits than its factorization.

331344121443133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15542219426.

The product of its digits is 373248, while the sum is 40.

The spelling of 331344121443133 in words is "three hundred thirty-one trillion, three hundred forty-four billion, one hundred twenty-one million, four hundred forty-three thousand, one hundred thirty-three".