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331424000471 is a prime number
BaseRepresentation
bin1001101001010100110…
…10001110100111010111
31011200110111201122112102
410310222122032213113
520412224021003341
6412130514312315
732641665344144
oct4645232164727
91150414648472
10331424000471
11118613231a23
125429528869b
132533a226725
14120807493cb
15894b31dc9b
hex4d2a68e9d7

331424000471 has 2 divisors, whose sum is σ = 331424000472. Its totient is φ = 331424000470.

The previous prime is 331424000437. The next prime is 331424000477. The reversal of 331424000471 is 174000424133.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 331424000471 - 210 = 331423999447 is a prime.

It is a super-3 number, since 3×3314240004713 (a number of 36 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331424000477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165712000235 + 165712000236.

It is an arithmetic number, because the mean of its divisors is an integer number (165712000236).

Almost surely, 2331424000471 is an apocalyptic number.

331424000471 is a deficient number, since it is larger than the sum of its proper divisors (1).

331424000471 is an equidigital number, since it uses as much as digits as its factorization.

331424000471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 29.

The spelling of 331424000471 in words is "three hundred thirty-one billion, four hundred twenty-four million, four hundred seventy-one", and thus it is an aban number.