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331424000437 is a prime number
BaseRepresentation
bin1001101001010100110…
…10001110100110110101
31011200110111201122111011
410310222122032212311
520412224021003222
6412130514312221
732641665344065
oct4645232164665
91150414648434
10331424000437
111186132319a2
1254295288671
132533a2266ca
14120807493a5
15894b31dc77
hex4d2a68e9b5

331424000437 has 2 divisors, whose sum is σ = 331424000438. Its totient is φ = 331424000436.

The previous prime is 331424000387. The next prime is 331424000471. The reversal of 331424000437 is 734000424133.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 174850258801 + 156573741636 = 418151^2 + 395694^2 .

It is a cyclic number.

It is not a de Polignac number, because 331424000437 - 215 = 331423967669 is a prime.

It is a super-3 number, since 3×3314240004373 (a number of 36 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 331424000399 and 331424000408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331424000477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165712000218 + 165712000219.

It is an arithmetic number, because the mean of its divisors is an integer number (165712000219).

Almost surely, 2331424000437 is an apocalyptic number.

It is an amenable number.

331424000437 is a deficient number, since it is larger than the sum of its proper divisors (1).

331424000437 is an equidigital number, since it uses as much as digits as its factorization.

331424000437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 31.

The spelling of 331424000437 in words is "three hundred thirty-one billion, four hundred twenty-four million, four hundred thirty-seven", and thus it is an aban number.