Base | Representation |
---|---|
bin | 100101101011011110001000… |
… | …0101000001100001001101111 |
3 | 1121110111101210222010110111202 |
4 | 1023112330100220030021233 |
5 | 321420122140144121143 |
6 | 3132520503245240115 |
7 | 126545012604161111 |
oct | 11326742050141157 |
9 | 1543441728113452 |
10 | 331430020301423 |
11 | 9667075610862a |
12 | 3120943726303b |
13 | 112c1941aa06a4 |
14 | 5bbb4273dd3b1 |
15 | 284b3c7081ab8 |
hex | 12d6f10a0c26f |
331430020301423 has 2 divisors, whose sum is σ = 331430020301424. Its totient is φ = 331430020301422.
The previous prime is 331430020301417. The next prime is 331430020301441. The reversal of 331430020301423 is 324103020034133.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331430020301423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331430020301123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165715010150711 + 165715010150712.
It is an arithmetic number, because the mean of its divisors is an integer number (165715010150712).
Almost surely, 2331430020301423 is an apocalyptic number.
331430020301423 is a deficient number, since it is larger than the sum of its proper divisors (1).
331430020301423 is an equidigital number, since it uses as much as digits as its factorization.
331430020301423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 331430020301423 its reverse (324103020034133), we get a palindrome (655533040335556).
The spelling of 331430020301423 in words is "three hundred thirty-one trillion, four hundred thirty billion, twenty million, three hundred one thousand, four hundred twenty-three".
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