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33144130031 is a prime number
BaseRepresentation
bin11110110111100010…
…110100100111101111
310011112212112020221112
4132313202310213233
51020334344130111
623120505422235
72252225312465
oct366742644757
9104485466845
1033144130031
1113068aa7501
12650ba9a97b
1331828a177c
141865c4c835
15cdeb8ce8b
hex7b78b49ef

33144130031 has 2 divisors, whose sum is σ = 33144130032. Its totient is φ = 33144130030.

The previous prime is 33144129959. The next prime is 33144130039. The reversal of 33144130031 is 13003144133.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 33144130031 - 214 = 33144113647 is a prime.

It is a super-2 number, since 2×331441300312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33144129979 and 33144130006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33144130039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16572065015 + 16572065016.

It is an arithmetic number, because the mean of its divisors is an integer number (16572065016).

Almost surely, 233144130031 is an apocalyptic number.

33144130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

33144130031 is an equidigital number, since it uses as much as digits as its factorization.

33144130031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 33144130031 its reverse (13003144133), we get a palindrome (46147274164).

The spelling of 33144130031 in words is "thirty-three billion, one hundred forty-four million, one hundred thirty thousand, thirty-one".