3315240041 has 2 divisors, whose sum is σ = 3315240042. Its totient is φ = 3315240040.

The previous prime is 3315240029. The next prime is 3315240043. The reversal of 3315240041 is 1400425133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2748800041 + 566440000 = 52429^2 + 23800^2 .

It is a cyclic number.

It is not a de Polignac number, because 3315240041 - 2²⁶ = 3248131177 is a prime.

It is a Sophie Germain prime.

Together with 3315240043, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3315239989 and 3315240016.

It is not a weakly prime, because it can be changed into another prime (3315240043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657620020 + 1657620021.

It is an arithmetic number, because the mean of its divisors is an integer number (1657620021).

Almost surely, 2^3315240041 is an apocalyptic number.

It is an amenable number.

3315240041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3315240041 is an equidigital number, since it uses as much as digits as its factorization.

3315240041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 3315240041 is about 57578.1212006783. The cubic root of 3315240041 is about 1491.0938982972.

Adding to 3315240041 its reverse (1400425133), we get a palindrome (4715665174).

The spelling of 3315240041 in words is "three billion, three hundred fifteen million, two hundred forty thousand, forty-one".