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33200030131999 is a prime number
BaseRepresentation
bin1111000110001111111000…
…00000001010011100011111
311100112220002011221120202121
413203013330000022130133
513322422130203210444
6154335514442403411
76664423460615563
oct743077400123437
9140486064846677
1033200030131999
11a640065539605
12388247ab00567
13156a9985ab3b3
1482ac663696a3
153c8920445084
hex1e31fc00a71f

33200030131999 has 2 divisors, whose sum is σ = 33200030132000. Its totient is φ = 33200030131998.

The previous prime is 33200030131949. The next prime is 33200030132029. The reversal of 33200030131999 is 99913103000233.

It is a strong prime.

It is an emirp because it is prime and its reverse (99913103000233) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33200030131999 - 213 = 33200030123807 is a prime.

It is a super-2 number, since 2×332000301319992 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33200030131949) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16600015065999 + 16600015066000.

It is an arithmetic number, because the mean of its divisors is an integer number (16600015066000).

Almost surely, 233200030131999 is an apocalyptic number.

33200030131999 is a deficient number, since it is larger than the sum of its proper divisors (1).

33200030131999 is an equidigital number, since it uses as much as digits as its factorization.

33200030131999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 118098, while the sum is 43.

The spelling of 33200030131999 in words is "thirty-three trillion, two hundred billion, thirty million, one hundred thirty-one thousand, nine hundred ninety-nine".