Base | Representation |
---|---|
bin | 11110111010111011… |
… | …110001011010000101 |
3 | 10011200211112122210002 |
4 | 132322323301122011 |
5 | 1020443424031432 |
6 | 23130300411045 |
7 | 2253515601353 |
oct | 367273613205 |
9 | 104624478702 |
10 | 33201002117 |
11 | 13098111328 |
12 | 6526b46a85 |
13 | 31915c4aaa |
14 | 186d6147d3 |
15 | ce4b73e62 |
hex | 7baef1685 |
33201002117 has 2 divisors, whose sum is σ = 33201002118. Its totient is φ = 33201002116.
The previous prime is 33201002047. The next prime is 33201002119. The reversal of 33201002117 is 71120010233.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30209568481 + 2991433636 = 173809^2 + 54694^2 .
It is a cyclic number.
It is not a de Polignac number, because 33201002117 - 220 = 33199953541 is a prime.
It is a super-2 number, since 2×332010021172 (a number of 22 digits) contains 22 as substring.
Together with 33201002119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33201002119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16600501058 + 16600501059.
It is an arithmetic number, because the mean of its divisors is an integer number (16600501059).
Almost surely, 233201002117 is an apocalyptic number.
It is an amenable number.
33201002117 is a deficient number, since it is larger than the sum of its proper divisors (1).
33201002117 is an equidigital number, since it uses as much as digits as its factorization.
33201002117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 20.
The spelling of 33201002117 in words is "thirty-three billion, two hundred one million, two thousand, one hundred seventeen".
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