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332162150025887 is a prime number
BaseRepresentation
bin100101110000110011000011…
…0111101011100101010011111
31121120002101120100100222100122
41023201212012331130222133
5322014121040401312022
63134241103554145155
7126651631504150526
oct11341460675345237
91546071510328318
10332162150025887
11969231a4270815
12313072bbb821bb
13113459aa8c9cbc
145c04a3b9354bd
152860476bec742
hex12e1986f5ca9f

332162150025887 has 2 divisors, whose sum is σ = 332162150025888. Its totient is φ = 332162150025886.

The previous prime is 332162150025833. The next prime is 332162150025889. The reversal of 332162150025887 is 788520051261233.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 332162150025887 - 226 = 332162082917023 is a prime.

It is a super-2 number, since 2×3321621500258872 (a number of 30 digits) contains 22 as substring.

Together with 332162150025889, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (332162150025889) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166081075012943 + 166081075012944.

It is an arithmetic number, because the mean of its divisors is an integer number (166081075012944).

Almost surely, 2332162150025887 is an apocalyptic number.

332162150025887 is a deficient number, since it is larger than the sum of its proper divisors (1).

332162150025887 is an equidigital number, since it uses as much as digits as its factorization.

332162150025887 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 332162150025887 in words is "three hundred thirty-two trillion, one hundred sixty-two billion, one hundred fifty million, twenty-five thousand, eight hundred eighty-seven".