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332433134013 = 3110811044671
BaseRepresentation
bin1001101011001101000…
…11110001000110111101
31011210001211120221111210
410311212203301012331
520421310340242023
6412415003435033
733006001005351
oct4654643610675
91153054527453
10332433134013
11118a90923992
1254517225a79
132546b310c76
1412138793461
1589a9c06593
hex4d668f11bd

332433134013 has 4 divisors (see below), whose sum is σ = 443244178688. Its totient is φ = 221622089340.

The previous prime is 332433133943. The next prime is 332433134027. The reversal of 332433134013 is 310431334233.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 332433134013 - 222 = 332428939709 is a prime.

It is a super-2 number, since 2×3324331340132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (332433134713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55405522333 + ... + 55405522338.

It is an arithmetic number, because the mean of its divisors is an integer number (110811044672).

Almost surely, 2332433134013 is an apocalyptic number.

It is an amenable number.

332433134013 is a deficient number, since it is larger than the sum of its proper divisors (110811044675).

332433134013 is a wasteful number, since it uses less digits than its factorization.

332433134013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110811044674.

The product of its (nonzero) digits is 23328, while the sum is 30.

Adding to 332433134013 its reverse (310431334233), we get a palindrome (642864468246).

The spelling of 332433134013 in words is "three hundred thirty-two billion, four hundred thirty-three million, one hundred thirty-four thousand, thirteen".

Divisors: 1 3 110811044671 332433134013