333000000213 has 4 divisors (see below), whose sum is σ = 444000000288. Its totient is φ = 222000000140.

The previous prime is 333000000211. The next prime is 333000000227. The reversal of 333000000213 is 312000000333.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 333000000213 - 2¹ = 333000000211 is a prime.

It is a super-2 number, since 2×333000000213² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 333000000192 and 333000000201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (333000000211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55500000033 + ... + 55500000038.

It is an arithmetic number, because the mean of its divisors is an integer number (111000000072).

Almost surely, 2^333000000213 is an apocalyptic number.

It is an amenable number.

333000000213 is a deficient number, since it is larger than the sum of its proper divisors (111000000075).

333000000213 is a wasteful number, since it uses less digits than its factorization.

333000000213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111000000074.

The product of its (nonzero) digits is 162, while the sum is 15.

Adding to 333000000213 its reverse (312000000333), we get a palindrome (645000000546).

The spelling of 333000000213 in words is "three hundred thirty-three billion, two hundred thirteen", and thus it is an aban number.