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33304040117 is a prime number
BaseRepresentation
bin11111000001000100…
…110101001010110101
310011222000102112100022
4133001010311022311
51021201313240432
623144421054525
72256206445605
oct370104651265
9104860375308
1033304040117
11131402982a7
126555557445
1331a9a6031a
14187d196c05
15cedc28b12
hex7c11352b5

33304040117 has 2 divisors, whose sum is σ = 33304040118. Its totient is φ = 33304040116.

The previous prime is 33304040041. The next prime is 33304040173. The reversal of 33304040117 is 71104040333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30468051601 + 2835988516 = 174551^2 + 53254^2 .

It is an emirp because it is prime and its reverse (71104040333) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33304040117 - 216 = 33303974581 is a prime.

It is a super-2 number, since 2×333040401172 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33304040197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16652020058 + 16652020059.

It is an arithmetic number, because the mean of its divisors is an integer number (16652020059).

Almost surely, 233304040117 is an apocalyptic number.

It is an amenable number.

33304040117 is a deficient number, since it is larger than the sum of its proper divisors (1).

33304040117 is an equidigital number, since it uses as much as digits as its factorization.

33304040117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 26.

The spelling of 33304040117 in words is "thirty-three billion, three hundred four million, forty thousand, one hundred seventeen".