3331021120213 has 2 divisors, whose sum is σ = 3331021120214. Its totient is φ = 3331021120212.

The previous prime is 3331021120211. The next prime is 3331021120291. The reversal of 3331021120213 is 3120211201333.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1822980631684 + 1508040488529 = 1350178^2 + 1228023^2 .

It is an emirp because it is prime and its reverse (3120211201333) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3331021120213 - 2¹ = 3331021120211 is a prime.

It is a super-2 number, since 2×3331021120213² (a number of 26 digits) contains 22 as substring.

Together with 3331021120211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3331021120211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665510560106 + 1665510560107.

It is an arithmetic number, because the mean of its divisors is an integer number (1665510560107).

Almost surely, 2^{3331021120213} is an apocalyptic number.

It is an amenable number.

3331021120213 is a deficient number, since it is larger than the sum of its proper divisors (1).

3331021120213 is an equidigital number, since it uses as much as digits as its factorization.

3331021120213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 3331021120213 its reverse (3120211201333), we get a palindrome (6451232321546).

The spelling of 3331021120213 in words is "three trillion, three hundred thirty-one billion, twenty-one million, one hundred twenty thousand, two hundred thirteen".