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33311122133 is a prime number
BaseRepresentation
bin11111000001011111…
…110110001011010101
310011222111202100001012
4133001133312023111
51021210121402013
623145232542005
72256323603102
oct370137661325
9104874670035
1033311122133
1113144295103
1265579b1905
1331ab36c973
1418800bbaa9
15cee6771a8
hex7c17f62d5

33311122133 has 2 divisors, whose sum is σ = 33311122134. Its totient is φ = 33311122132.

The previous prime is 33311122129. The next prime is 33311122139. The reversal of 33311122133 is 33122111333.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21215961649 + 12095160484 = 145657^2 + 109978^2 .

It is an emirp because it is prime and its reverse (33122111333) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33311122133 - 22 = 33311122129 is a prime.

It is a super-2 number, since 2×333111221332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33311122099 and 33311122108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33311122139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16655561066 + 16655561067.

It is an arithmetic number, because the mean of its divisors is an integer number (16655561067).

Almost surely, 233311122133 is an apocalyptic number.

It is an amenable number.

33311122133 is a deficient number, since it is larger than the sum of its proper divisors (1).

33311122133 is an equidigital number, since it uses as much as digits as its factorization.

33311122133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 23.

Adding to 33311122133 its reverse (33122111333), we get a palindrome (66433233466).

The spelling of 33311122133 in words is "thirty-three billion, three hundred eleven million, one hundred twenty-two thousand, one hundred thirty-three".