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3332040022013 is a prime number
BaseRepresentation
bin110000011111001101000…
…011111101011111111101
3102210112120121011001200012
4300133031003331133331
5414043004221201023
611030415033313005
7462506025606353
oct60371503753775
912715517131605
103332040022013
1110751237a980a
12459931565765
131b2296571801
14b73b33997d3
155ba19b97978
hex307cd0fd7fd

3332040022013 has 2 divisors, whose sum is σ = 3332040022014. Its totient is φ = 3332040022012.

The previous prime is 3332040021983. The next prime is 3332040022019. The reversal of 3332040022013 is 3102200402333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2951255998084 + 380784023929 = 1717922^2 + 617077^2 .

It is a cyclic number.

It is not a de Polignac number, because 3332040022013 - 218 = 3332039759869 is a prime.

It is a super-2 number, since 2×33320400220132 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3332040022013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3332040022019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1666020011006 + 1666020011007.

It is an arithmetic number, because the mean of its divisors is an integer number (1666020011007).

Almost surely, 23332040022013 is an apocalyptic number.

It is an amenable number.

3332040022013 is a deficient number, since it is larger than the sum of its proper divisors (1).

3332040022013 is an equidigital number, since it uses as much as digits as its factorization.

3332040022013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 3332040022013 its reverse (3102200402333), we get a palindrome (6434240424346).

The spelling of 3332040022013 in words is "three trillion, three hundred thirty-two billion, forty million, twenty-two thousand, thirteen".