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33325525141 is a prime number
BaseRepresentation
bin11111000010010110…
…110010100010010101
310012000111212002020221
4133002112302202111
51021222313301031
623150505354341
72256560201266
oct370226624225
9105014762227
1033325525141
1113151432317
1265607989b1
1331b134365c
141881d8a96d
15d00a6ea11
hex7c25b2895

33325525141 has 2 divisors, whose sum is σ = 33325525142. Its totient is φ = 33325525140.

The previous prime is 33325525111. The next prime is 33325525193. The reversal of 33325525141 is 14152552333.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17676766116 + 15648759025 = 132954^2 + 125095^2 .

It is a cyclic number.

It is not a de Polignac number, because 33325525141 - 29 = 33325524629 is a prime.

It is a super-2 number, since 2×333255251412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33325525097 and 33325525106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33325525111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16662762570 + 16662762571.

It is an arithmetic number, because the mean of its divisors is an integer number (16662762571).

Almost surely, 233325525141 is an apocalyptic number.

It is an amenable number.

33325525141 is a deficient number, since it is larger than the sum of its proper divisors (1).

33325525141 is an equidigital number, since it uses as much as digits as its factorization.

33325525141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54000, while the sum is 34.

The spelling of 33325525141 in words is "thirty-three billion, three hundred twenty-five million, five hundred twenty-five thousand, one hundred forty-one".