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33401001331031 is a prime number
BaseRepresentation
bin1111001100000110001101…
…10100011100100101010111
311101021002211012201021212112
413212003012310130211113
513334220222320043111
6155012112544541235
710015066643620625
oct746030664344527
9141232735637775
1033401001331031
11a708315541a34
1238b540792181b
131583915b92449
1483688d41c515
153cdc83cabe8b
hex1e60c6d1c957

33401001331031 has 2 divisors, whose sum is σ = 33401001331032. Its totient is φ = 33401001331030.

The previous prime is 33401001330971. The next prime is 33401001331051. The reversal of 33401001331031 is 13013310010433.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 33401001331031 - 26 = 33401001330967 is a prime.

It is a super-2 number, since 2×334010013310312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33401001330988 and 33401001331006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33401001331051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16700500665515 + 16700500665516.

It is an arithmetic number, because the mean of its divisors is an integer number (16700500665516).

Almost surely, 233401001331031 is an apocalyptic number.

33401001331031 is a deficient number, since it is larger than the sum of its proper divisors (1).

33401001331031 is an equidigital number, since it uses as much as digits as its factorization.

33401001331031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 33401001331031 its reverse (13013310010433), we get a palindrome (46414311341464).

The spelling of 33401001331031 in words is "thirty-three trillion, four hundred one billion, one million, three hundred thirty-one thousand, thirty-one".