Base | Representation |
---|---|
bin | 1001101110001001001… |
… | …00101011111001101010 |
3 | 1011221010202120001010121 |
4 | 10313010210223321222 |
5 | 20433023132330010 |
6 | 413235310433454 |
7 | 33063042560143 |
oct | 4670444537152 |
9 | 1157122501117 |
10 | 334010433130 |
11 | 119720200080 |
12 | 5489750288a |
13 | 2566002915a |
14 | 12248058aca |
15 | 8a4d41e3da |
hex | 4dc492be6a |
334010433130 has 64 divisors (see below), whose sum is σ = 672044034816. Its totient is φ = 118465600000.
The previous prime is 334010433077. The next prime is 334010433173. The reversal of 334010433130 is 31334010433.
It is a happy number.
It is a super-2 number, since 2×3340104331302 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 334010433095 and 334010433104.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24802779 + ... + 24816241.
It is an arithmetic number, because the mean of its divisors is an integer number (10500688044).
Almost surely, 2334010433130 is an apocalyptic number.
334010433130 is an abundant number, since it is smaller than the sum of its proper divisors (338033601686).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
334010433130 is a wasteful number, since it uses less digits than its factorization.
334010433130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19023.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 334010433130 its reverse (31334010433), we get a palindrome (365344443563).
The spelling of 334010433130 in words is "three hundred thirty-four billion, ten million, four hundred thirty-three thousand, one hundred thirty".
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