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334030020032 = 268775951219
BaseRepresentation
bin1001101110001011011…
…11011001110111000000
31011221012010102011022102
410313011233121313000
520433043141120112
6413241250325532
733063401215622
oct4670557316700
91157163364272
10334030020032
11119730268aa5
12548a1b898a8
13256640c6537
141224a8b6c12
158a4eedcbc2
hex4dc5bd9dc0

334030020032 has 28 divisors (see below), whose sum is σ = 663596737320. Its totient is φ = 166824542976.

The previous prime is 334030020013. The next prime is 334030020083. The reversal of 334030020032 is 230020030433.

It is a super-2 number, since 2×3340300200322 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 334030019986 and 334030020013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2919482 + ... + 3031737.

Almost surely, 2334030020032 is an apocalyptic number.

334030020032 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

334030020032 is a deficient number, since it is larger than the sum of its proper divisors (329566717288).

334030020032 is an equidigital number, since it uses as much as digits as its factorization.

334030020032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5952108 (or 5952098 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 20.

Adding to 334030020032 its reverse (230020030433), we get a palindrome (564050050465).

The spelling of 334030020032 in words is "three hundred thirty-four billion, thirty million, twenty thousand, thirty-two".

Divisors: 1 2 4 8 16 32 64 877 1754 3508 7016 14032 28064 56128 5951219 11902438 23804876 47609752 95219504 190439008 380878016 5219219063 10438438126 20876876252 41753752504 83507505008 167015010016 334030020032