3340431041 has 2 divisors, whose sum is σ = 3340431042. Its totient is φ = 3340431040.

The previous prime is 3340431011. The next prime is 3340431103. The reversal of 3340431041 is 1401340433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3325252225 + 15178816 = 57665^2 + 3896^2 .

It is an emirp because it is prime and its reverse (1401340433) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3340431041 is a prime.

It is a super-2 number, since 2×3340431041² = 22316959079352687362, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3340430998 and 3340431016.

It is not a weakly prime, because it can be changed into another prime (3340431011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670215520 + 1670215521.

It is an arithmetic number, because the mean of its divisors is an integer number (1670215521).

Almost surely, 2^3340431041 is an apocalyptic number.

It is an amenable number.

3340431041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340431041 is an equidigital number, since it uses as much as digits as its factorization.

3340431041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 3340431041 is about 57796.4621841164. The cubic root of 3340431041 is about 1494.8610872297.

Adding to 3340431041 its reverse (1401340433), we get a palindrome (4741771474).

The spelling of 3340431041 in words is "three billion, three hundred forty million, four hundred thirty-one thousand, forty-one".