334049477 has 2 divisors, whose sum is σ = 334049478. Its totient is φ = 334049476.

The previous prime is 334049461. The next prime is 334049479. The reversal of 334049477 is 774940433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 199628641 + 134420836 = 14129^2 + 11594^2 .

It is a cyclic number.

It is not a de Polignac number, because 334049477 - 2⁴ = 334049461 is a prime.

It is a super-3 number, since 3×334049477³ (a number of 27 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 334049479, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334049479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167024738 + 167024739.

It is an arithmetic number, because the mean of its divisors is an integer number (167024739).

Almost surely, 2^334049477 is an apocalyptic number.

It is an amenable number.

334049477 is a deficient number, since it is larger than the sum of its proper divisors (1).

334049477 is an equidigital number, since it uses as much as digits as its factorization.

334049477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 254016, while the sum is 41.

The square root of 334049477 is about 18277.0204628654. The cubic root of 334049477 is about 693.8574654613.

The spelling of 334049477 in words is "three hundred thirty-four million, forty-nine thousand, four hundred seventy-seven".