334050050433 has 8 divisors (see below), whose sum is σ = 485890982496. Its totient is φ = 202454576000.

The previous prime is 334050050423. The next prime is 334050050459.

334050050433 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 334050050433 - 2⁸ = 334050050177 is a prime.

It is a super-2 number, since 2×334050050433² (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 334050050433.

It is not an unprimeable number, because it can be changed into a prime (334050050423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5061364368 + ... + 5061364433.

It is an arithmetic number, because the mean of its divisors is an integer number (60736372812).

Almost surely, 2^334050050433 is an apocalyptic number.

334050050433 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

It is an amenable number.

334050050433 is a deficient number, since it is larger than the sum of its proper divisors (151840932063).

334050050433 is a wasteful number, since it uses less digits than its factorization.

334050050433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10122728815.

The product of its (nonzero) digits is 32400, while the sum is 30.

It can be divided in two parts, 3340500 and 50433, that added together give a palindrome (3390933).

The spelling of 334050050433 in words is "three hundred thirty-four billion, fifty million, fifty thousand, four hundred thirty-three".