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3341213433143 = 10393215797337
BaseRepresentation
bin110000100111101111110…
…101101111110100110111
3102211102020220112122000222
4300213233311233310313
5414220301114330033
611034533211324555
7463252245404255
oct60475765576467
912742226478028
103341213433143
111079000972323
1245b67175075b
131b30c8c29931
14b7a038315d5
155bda51ca598
hex309efd6fd37

3341213433143 has 4 divisors (see below), whose sum is σ = 3344429231520. Its totient is φ = 3337997634768.

The previous prime is 3341213433133. The next prime is 3341213433149. The reversal of 3341213433143 is 3413343121433.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3341213433143 - 214 = 3341213416759 is a prime.

It is a super-2 number, since 2×33412134331432 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3341213433149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1607897630 + ... + 1607899707.

It is an arithmetic number, because the mean of its divisors is an integer number (836107307880).

Almost surely, 23341213433143 is an apocalyptic number.

3341213433143 is a deficient number, since it is larger than the sum of its proper divisors (3215798377).

3341213433143 is a wasteful number, since it uses less digits than its factorization.

3341213433143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3215798376.

The product of its digits is 93312, while the sum is 35.

Adding to 3341213433143 its reverse (3413343121433), we get a palindrome (6754556554576).

The spelling of 3341213433143 in words is "three trillion, three hundred forty-one billion, two hundred thirteen million, four hundred thirty-three thousand, one hundred forty-three".

Divisors: 1 1039 3215797337 3341213433143