Base | Representation |
---|---|
bin | 11111001000000011… |
… | …110011101100010001 |
3 | 10012021011220111112201 |
4 | 133020003303230101 |
5 | 1021421312244213 |
6 | 23204204323201 |
7 | 2262131422060 |
oct | 371003635421 |
9 | 105234814481 |
10 | 33421212433 |
11 | 131a0448624 |
12 | 6588843501 |
13 | 31c810715b |
14 | 18909781d7 |
15 | d091716dd |
hex | 7c80f3b11 |
33421212433 has 4 divisors (see below), whose sum is σ = 38195671360. Its totient is φ = 28646753508.
The previous prime is 33421212413. The next prime is 33421212463.
It is a happy number.
33421212433 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 33421212433 - 221 = 33419115281 is a prime.
It is a super-2 number, since 2×334212124332 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (33421212413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2387229453 + ... + 2387229466.
It is an arithmetic number, because the mean of its divisors is an integer number (9548917840).
Almost surely, 233421212433 is an apocalyptic number.
It is an amenable number.
33421212433 is a deficient number, since it is larger than the sum of its proper divisors (4774458927).
33421212433 is an equidigital number, since it uses as much as digits as its factorization.
33421212433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4774458926.
The product of its digits is 10368, while the sum is 28.
The spelling of 33421212433 in words is "thirty-three billion, four hundred twenty-one million, two hundred twelve thousand, four hundred thirty-three".
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