Base | Representation |
---|---|
bin | 1111001101010010101001… |
… | …11011000111110001011010 |
3 | 11101102000202021111100122111 |
4 | 13212221110323013301122 |
5 | 13340403244234314010 |
6 | 155043021113142534 |
7 | 10021051634054512 |
oct | 746512473076132 |
9 | 141360667440574 |
10 | 33442040151130 |
11 | a723764918986 |
12 | 390135b6baa4a |
13 | 1587756224650 |
14 | 838863960842 |
15 | 3ced86a9258a |
hex | 1e6a54ec7c5a |
33442040151130 has 32 divisors (see below), whose sum is σ = 64826455904784. Its totient is φ = 12347764056576.
The previous prime is 33442040151109. The next prime is 33442040151167. The reversal of 33442040151130 is 3115104024433.
It can be written as a sum of positive squares in 8 ways, for example, as 3466623200769 + 29975416950361 = 1861887^2 + 5474981^2 .
It is a super-2 number, since 2×334420401511302 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 33442040151092 and 33442040151101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28361902 + ... + 29517478.
Almost surely, 233442040151130 is an apocalyptic number.
33442040151130 is a deficient number, since it is larger than the sum of its proper divisors (31384415753654).
33442040151130 is a wasteful number, since it uses less digits than its factorization.
33442040151130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1378210.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 33442040151130 its reverse (3115104024433), we get a palindrome (36557144175563).
The spelling of 33442040151130 in words is "thirty-three trillion, four hundred forty-two billion, forty million, one hundred fifty-one thousand, one hundred thirty".
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