Base | Representation |
---|---|
bin | 110000101011010010001… |
… | …000100101001111000011 |
3 | 102211210001111111021220201 |
4 | 300223102020211033003 |
5 | 414301040031140230 |
6 | 11040402033350031 |
7 | 463445316023404 |
oct | 60532210451703 |
9 | 12753044437821 |
10 | 3345010021315 |
11 | 107a679a531a6 |
12 | 460351108317 |
13 | 1b358266b101 |
14 | b7c83b559ab |
15 | 5c0286705ca |
hex | 30ad22253c3 |
3345010021315 has 32 divisors (see below), whose sum is σ = 4080954729600. Its totient is φ = 2631779610624.
The previous prime is 3345010021289. The next prime is 3345010021349. The reversal of 3345010021315 is 5131200105433.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 3345010021315 - 213 = 3345010013123 is a prime.
It is a super-3 number, since 3×33450100213153 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 49560922 + ... + 49628368.
It is an arithmetic number, because the mean of its divisors is an integer number (127529835300).
Almost surely, 23345010021315 is an apocalyptic number.
3345010021315 is a deficient number, since it is larger than the sum of its proper divisors (735944708285).
3345010021315 is a wasteful number, since it uses less digits than its factorization.
3345010021315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68191.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 3345010021315 its reverse (5131200105433), we get a palindrome (8476210126748).
The spelling of 3345010021315 in words is "three trillion, three hundred forty-five billion, ten million, twenty-one thousand, three hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •