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5131200105433 is a prime number
BaseRepresentation
bin100101010101011001101…
…0111000000101111011001
3200011112112011021001012101
41022222303113000233121
51133032144211333213
614525124002043401
71036500631154143
oct112526327005731
920145464231171
105131200105433
1116a9147764666
126aa564649561
132b2b4079924c
1413a4cc3abc93
158d71aae1bdd
hex4aab35c0bd9

5131200105433 has 2 divisors, whose sum is σ = 5131200105434. Its totient is φ = 5131200105432.

The previous prime is 5131200105377. The next prime is 5131200105439. The reversal of 5131200105433 is 3345010021315.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3278029744089 + 1853170361344 = 1810533^2 + 1361312^2 .

It is a cyclic number.

It is not a de Polignac number, because 5131200105433 - 237 = 4993761151961 is a prime.

It is a super-2 number, since 2×51312001054332 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5131200105439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565600052716 + 2565600052717.

It is an arithmetic number, because the mean of its divisors is an integer number (2565600052717).

Almost surely, 25131200105433 is an apocalyptic number.

It is an amenable number.

5131200105433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5131200105433 is an equidigital number, since it uses as much as digits as its factorization.

5131200105433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 5131200105433 its reverse (3345010021315), we get a palindrome (8476210126748).

The spelling of 5131200105433 in words is "five trillion, one hundred thirty-one billion, two hundred million, one hundred five thousand, four hundred thirty-three".