3345401451053 has 2 divisors, whose sum is σ = 3345401451054. Its totient is φ = 3345401451052.

The previous prime is 3345401451017. The next prime is 3345401451089. The reversal of 3345401451053 is 3501541045433.

3345401451053 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (3345401451017) and next prime (3345401451089).

It can be written as a sum of positive squares in only one way, i.e., 2866069544809 + 479331906244 = 1692947^2 + 692338^2 .

It is a cyclic number.

It is not a de Polignac number, because 3345401451053 - 2¹⁰ = 3345401450029 is a prime.

It is a super-2 number, since 2×3345401451053² (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3345401450998 and 3345401451016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3345401459053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1672700725526 + 1672700725527.

It is an arithmetic number, because the mean of its divisors is an integer number (1672700725527).

Almost surely, 2^{3345401451053} is an apocalyptic number.

It is an amenable number.

3345401451053 is a deficient number, since it is larger than the sum of its proper divisors (1).

3345401451053 is an equidigital number, since it uses as much as digits as its factorization.

3345401451053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 3345401451053 its reverse (3501541045433), we get a palindrome (6846942496486).

The spelling of 3345401451053 in words is "three trillion, three hundred forty-five billion, four hundred one million, four hundred fifty-one thousand, fifty-three".