3345502021 has 2 divisors, whose sum is σ = 3345502022. Its totient is φ = 3345502020.

The previous prime is 3345502019. The next prime is 3345502049. The reversal of 3345502021 is 1202055433.

3345502021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3345349921 + 152100 = 57839^2 + 390^2 .

It is an emirp because it is prime and its reverse (1202055433) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3345502021 - 2¹ = 3345502019 is a prime.

It is a super-2 number, since 2×3345502021² = 22384767545030168882, which contains 22 as substring.

Together with 3345502019, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3345502081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1672751010 + 1672751011.

It is an arithmetic number, because the mean of its divisors is an integer number (1672751011).

Almost surely, 2^3345502021 is an apocalyptic number.

It is an amenable number.

3345502021 is a deficient number, since it is larger than the sum of its proper divisors (1).

3345502021 is an equidigital number, since it uses as much as digits as its factorization.

3345502021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 25.

The square root of 3345502021 is about 57840.3148418125. The cubic root of 3345502021 is about 1495.6171351740.

Adding to 3345502021 its reverse (1202055433), we get a palindrome (4547557454).

The spelling of 3345502021 in words is "three billion, three hundred forty-five million, five hundred two thousand, twenty-one".