335040405311 has 2 divisors, whose sum is σ = 335040405312. Its totient is φ = 335040405310.

The previous prime is 335040405181. The next prime is 335040405313. The reversal of 335040405311 is 113504040533.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 335040405311 - 2¹⁸ = 335040143167 is a prime.

It is a super-2 number, since 2×335040405311² (a number of 24 digits) contains 22 as substring.

Together with 335040405313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (335040405313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167520202655 + 167520202656.

It is an arithmetic number, because the mean of its divisors is an integer number (167520202656).

Almost surely, 2^335040405311 is an apocalyptic number.

335040405311 is a deficient number, since it is larger than the sum of its proper divisors (1).

335040405311 is an equidigital number, since it uses as much as digits as its factorization.

335040405311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 335040405311 its reverse (113504040533), we get a palindrome (448544445844).

The spelling of 335040405311 in words is "three hundred thirty-five billion, forty million, four hundred five thousand, three hundred eleven".