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3351221112949 is a prime number
BaseRepresentation
bin110000110001000100010…
…110000001000001110101
3102212101002100202102212121
4300301010112001001311
5414401300101103244
611043310230515541
7464055245313313
oct60610426010165
912771070672777
103351221112949
111082276a52286
124615a5205bb1
131b40323a5868
14b82b29d30b3
155c28daa3c84
hex30c44581075

3351221112949 has 2 divisors, whose sum is σ = 3351221112950. Its totient is φ = 3351221112948.

The previous prime is 3351221112947. The next prime is 3351221113027. The reversal of 3351221112949 is 9492111221533.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3090539388049 + 260681724900 = 1757993^2 + 510570^2 .

It is an emirp because it is prime and its reverse (9492111221533) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3351221112949 - 21 = 3351221112947 is a prime.

It is a super-2 number, since 2×33512211129492 (a number of 26 digits) contains 22 as substring.

Together with 3351221112947, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3351221112947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1675610556474 + 1675610556475.

It is an arithmetic number, because the mean of its divisors is an integer number (1675610556475).

Almost surely, 23351221112949 is an apocalyptic number.

It is an amenable number.

3351221112949 is a deficient number, since it is larger than the sum of its proper divisors (1).

3351221112949 is an equidigital number, since it uses as much as digits as its factorization.

3351221112949 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 116640, while the sum is 43.

The spelling of 3351221112949 in words is "three trillion, three hundred fifty-one billion, two hundred twenty-one million, one hundred twelve thousand, nine hundred forty-nine".