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33543018149 is a prime number
BaseRepresentation
bin11111001111010100…
…011101011010100101
310012120200002212120112
4133033110131122211
51022144003040044
623224235142405
72265140643554
oct371724353245
9105520085515
1033543018149
1113253183003
1266015a4a05
133217413c44
1418a2c03d9b
15d14bd209e
hex7cf51d6a5

33543018149 has 2 divisors, whose sum is σ = 33543018150. Its totient is φ = 33543018148.

The previous prime is 33543018107. The next prime is 33543018151. The reversal of 33543018149 is 94181034533.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27919068100 + 5623950049 = 167090^2 + 74993^2 .

It is an emirp because it is prime and its reverse (94181034533) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-33543018149 is a prime.

It is a super-2 number, since 2×335430181492 (a number of 22 digits) contains 22 as substring.

Together with 33543018151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33543018199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16771509074 + 16771509075.

It is an arithmetic number, because the mean of its divisors is an integer number (16771509075).

Almost surely, 233543018149 is an apocalyptic number.

It is an amenable number.

33543018149 is a deficient number, since it is larger than the sum of its proper divisors (1).

33543018149 is an equidigital number, since it uses as much as digits as its factorization.

33543018149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 33543018149 in words is "thirty-three billion, five hundred forty-three million, eighteen thousand, one hundred forty-nine".