Base | Representation |
---|---|
bin | 11111101001011001… |
… | …000000111101011101 |
3 | 10020201011011012000121 |
4 | 133221121000331131 |
5 | 1024042441414213 |
6 | 23335502154541 |
7 | 2312031542455 |
oct | 375131007535 |
9 | 106634135017 |
10 | 33980419933 |
11 | 13458074489 |
12 | 6703b82a51 |
13 | 3286c1c575 |
14 | 1904d42d65 |
15 | d3d2d288d |
hex | 7e9640f5d |
33980419933 has 2 divisors, whose sum is σ = 33980419934. Its totient is φ = 33980419932.
The previous prime is 33980419897. The next prime is 33980419969. The reversal of 33980419933 is 33991408933.
It is a balanced prime because it is at equal distance from previous prime (33980419897) and next prime (33980419969).
It can be written as a sum of positive squares in only one way, i.e., 26309813209 + 7670606724 = 162203^2 + 87582^2 .
It is a cyclic number.
It is not a de Polignac number, because 33980419933 - 217 = 33980288861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33980719933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16990209966 + 16990209967.
It is an arithmetic number, because the mean of its divisors is an integer number (16990209967).
Almost surely, 233980419933 is an apocalyptic number.
It is an amenable number.
33980419933 is a deficient number, since it is larger than the sum of its proper divisors (1).
33980419933 is an equidigital number, since it uses as much as digits as its factorization.
33980419933 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1889568, while the sum is 52.
The spelling of 33980419933 in words is "thirty-three billion, nine hundred eighty million, four hundred nineteen thousand, nine hundred thirty-three".
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