Base | Representation |
---|---|
bin | 110001011110100000011… |
… | …110010001100110111111 |
3 | 110001001000122022221200021 |
4 | 301132200132101212333 |
5 | 421201210411002033 |
6 | 11121535500313011 |
7 | 500433311146600 |
oct | 61364036214677 |
9 | 13031018287607 |
10 | 3400011422143 |
11 | 10a0a3389a766 |
12 | 46ab40b42767 |
13 | 1b880963a1bb |
14 | ba7c07cdda7 |
15 | 5d697146b2d |
hex | 317a07919bf |
3400011422143 has 6 divisors (see below), whose sum is σ = 3955115327856. Its totient is φ = 2914295504652.
The previous prime is 3400011422131. The next prime is 3400011422173. The reversal of 3400011422143 is 3412241100043.
It is not a de Polignac number, because 3400011422143 - 213 = 3400011413951 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3400011422173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 34693994055 + ... + 34693994152.
It is an arithmetic number, because the mean of its divisors is an integer number (659185887976).
Almost surely, 23400011422143 is an apocalyptic number.
3400011422143 is a deficient number, since it is larger than the sum of its proper divisors (555103905713).
3400011422143 is an equidigital number, since it uses as much as digits as its factorization.
3400011422143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69387988221 (or 69387988214 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 3400011422143 its reverse (3412241100043), we get a palindrome (6812252522186).
The spelling of 3400011422143 in words is "three trillion, four hundred billion, eleven million, four hundred twenty-two thousand, one hundred forty-three".
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