340001302143311 has 2 divisors, whose sum is σ = 340001302143312. Its totient is φ = 340001302143310.

The previous prime is 340001302143233. The next prime is 340001302143313. The reversal of 340001302143311 is 113341203100043.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 340001302143311 - 2¹⁰ = 340001302142287 is a prime.

Together with 340001302143313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (340001302143313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170000651071655 + 170000651071656.

It is an arithmetic number, because the mean of its divisors is an integer number (170000651071656).

Almost surely, 2^{340001302143311} is an apocalyptic number.

340001302143311 is a deficient number, since it is larger than the sum of its proper divisors (1).

340001302143311 is an equidigital number, since it uses as much as digits as its factorization.

340001302143311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 340001302143311 its reverse (113341203100043), we get a palindrome (453342505243354).

The spelling of 340001302143311 in words is "three hundred forty trillion, one billion, three hundred two million, one hundred forty-three thousand, three hundred eleven".