Base | Representation |
---|---|
bin | 1100101010101000… |
… | …0111111011000011 |
3 | 22202221202221020021 |
4 | 3022222013323003 |
5 | 23430402241011 |
6 | 1321214354311 |
7 | 150153602305 |
oct | 31252077303 |
9 | 8687687207 |
10 | 3400040131 |
11 | 1495263524 |
12 | 7aa7bb997 |
13 | 42253b187 |
14 | 2437bb975 |
15 | 14d764471 |
hex | caa87ec3 |
3400040131 has 2 divisors, whose sum is σ = 3400040132. Its totient is φ = 3400040130.
The previous prime is 3400040129. The next prime is 3400040179. The reversal of 3400040131 is 1310400043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3400040131 - 21 = 3400040129 is a prime.
It is a super-2 number, since 2×34000401312 = 23120545784820994322, which contains 22 as substring.
Together with 3400040129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3400043131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700020065 + 1700020066.
It is an arithmetic number, because the mean of its divisors is an integer number (1700020066).
Almost surely, 23400040131 is an apocalyptic number.
3400040131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3400040131 is an equidigital number, since it uses as much as digits as its factorization.
3400040131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 16.
The square root of 3400040131 is about 58309.8630679236. The cubic root of 3400040131 is about 1503.7005123354.
Adding to 3400040131 its reverse (1310400043), we get a palindrome (4710440174).
The spelling of 3400040131 in words is "three billion, four hundred million, forty thousand, one hundred thirty-one".
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