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340010241341413 is a prime number
BaseRepresentation
bin100110101001111001100110…
…1101001111011011111100101
31122120212122212022202122110211
41031103303031221323133211
5324031211433240411123
63203050314252015421
7131421633513516046
oct11523631551733745
91576778768678424
10340010241341413
1199379596208a15
1232174319a61571
1311794a9c68a2c6
145dd68251388cd
1529496a770c40d
hex1353ccda7b7e5

340010241341413 has 2 divisors, whose sum is σ = 340010241341414. Its totient is φ = 340010241341412.

The previous prime is 340010241341411. The next prime is 340010241341423. The reversal of 340010241341413 is 314143142010043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 260145866805444 + 79864374535969 = 16129038^2 + 8936687^2 .

It is a cyclic number.

It is not a de Polignac number, because 340010241341413 - 21 = 340010241341411 is a prime.

Together with 340010241341411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (340010241341411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170005120670706 + 170005120670707.

It is an arithmetic number, because the mean of its divisors is an integer number (170005120670707).

Almost surely, 2340010241341413 is an apocalyptic number.

It is an amenable number.

340010241341413 is a deficient number, since it is larger than the sum of its proper divisors (1).

340010241341413 is an equidigital number, since it uses as much as digits as its factorization.

340010241341413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 340010241341413 its reverse (314143142010043), we get a palindrome (654153383351456).

The spelling of 340010241341413 in words is "three hundred forty trillion, ten billion, two hundred forty-one million, three hundred forty-one thousand, four hundred thirteen".